How many miles could the car go with that energy?

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The discussion revolves around calculating how far a car can travel using the energy from a 362 mg drop of gasoline, given that one gallon produces 1.1 x 10^8 J of energy for twenty miles. Participants note the need to convert the gasoline mass from milligrams to kilograms for proper energy calculations. There is confusion regarding the relevance of Einstein's equation E=mc^2, with some arguing it is unnecessary for this problem. Instead, the focus should be on understanding how car engines utilize energy. Ultimately, the goal is to relate the energy from the gasoline drop to the distance it can propel the car.
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Homework Statement


Suppose one gallon of gasoline produces 1.1 x 10^8 J of energy, and this energy is sufficient to operate a car for twenty miles. If a 362 mg drop of gasoline could be converted completely into thermal energy, how many miles could the car go with that energy?


Homework Equations


I cannot find a conversion for 1 gallon of gasoline to kilograms. Is it even necessary?? Also, for the 362 mg drop. I know they need to be in kilograms in order for the energy to be in JOULES.


The Attempt at a Solution


I used the equation E0=mc^2. I plugged in 1.1 x 10^8 J for the energy and I didn't know what to use for the mass but I know that once I do that I can use the value for C using the same equation, except the second time the mass would be for the 362 mg drop.
 
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To convert gallons of gasoline to kilograms, you need to know the density of gasoline.

This problem has nothing to do with relativity. Don't use E=mc^2. Think about how a car engine works.
 
It DOES has to do with relativity because E0=mc^2 is the hint that the website (for this HW problem) gave to solve for the problem. It may not be the bulk of the problem but it is at least partially part of the process.
Also, how can i relate this problem to how a car engine works?
 
You are told how much energy is sufficient to operate a car for twenty miles; Calculate the rest energy of that drop of gas and compare.
 
I see. I misunderstood. I assumed they wanted an answer to a realistic problem. Ignore what I wrote before.
 
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