How Many Revolutions Does a Car Make From Rest to a Specific Acceleration?

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A user seeks to determine how many revolutions a car makes from rest while accelerating at 1.20 m/s² on a curve with a radius of 110 m until its total acceleration reaches 2.20 m/s². The discussion highlights the need to calculate the time, distance, and angle to transition between accelerations, emphasizing that total acceleration is the vector sum of tangential and centripetal acceleration. The user suggests solving for centripetal acceleration using the formula Ac = v²/r, followed by finding velocity and applying kinematic equations. The thread indicates a lack of clarity on how to approach the problem, particularly regarding the necessary calculations. Overall, the conversation revolves around understanding the relationship between acceleration, distance, and revolutions in the context of circular motion.
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# of Revolutions made

I had the same question as someone else here, but they figured it out but nothing was said in the post. As such, I was asked to make a new thread..
So, pretty much, I have this question:

1. Homework Statement
A car starts from rest on a curve with a radius of 110 m and accelerates at 1.20 m/s^2. How many revolutions will the car have gone through when the magnitude of its total acceleration is 2.20 m/s^2?


2. Homework Equations

theta (final)=theta (initial)+omega*(delta)t+(a*(delta)t^2)/2*r

3. The Attempt at a Solution

i just have no idea how to figure out the time or the distance (or the angle) it takes the car to get from one acceleration to another...
 
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Total acceleration = vector sum of tangential acceleration and centripetal acceleration.
Solve for centripetal acceleration.

Ac = v^2/r
Solve for v.

Use a kinematic equation with v, you should be done.
 
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