How many roots does the equation y^2 = x^3 + x + 6 (mod 5 * 9^2) have?

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The discussion focuses on finding the roots of the equation y^2 = x^3 + x + 6 modulo 5 * 9^2. Initial contributions identify several roots modulo 5, including (0,1), (0,4), (2,1), (2,4), (3,1), (3,4), (4,2), and (4,3). Participants clarify that the equation should be treated as a function of the form g(x,y) = x^3 + x + 6 (mod 5 * 9^2) - y^2. There is a distinction made between referring to the equation as a function versus an equation. The conversation emphasizes the need for a proper understanding of the mathematical structure involved.
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What are the 4 roots of a function y^2 = x^3 + x + 6 (mod 5 * 9^2)?

I don't know where to start a problem like this. The roots mod 5 are (0,1) (0,4) (2,1) (2,4) (3,1) (3,4) (4,2) (4,3) if that helps
 
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is this a function of the form

g(x,y) = x^3 + x + 6 * (mod 5 * 9^2) - y^2
 
I think it is meant to be in the form I posted
 
What you posted is not a "function", it is an "equation". It would be equivalent to
f(x)= 0 where f is the function jedishrfu gave.
 
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