How Many Volts Are Needed for My Motor to Lift 12kg in a Time-Lapse Project?

AI Thread Summary
To lift a 12kg load vertically to a height of 1.3m in 60 minutes, the motor must exert a force of 117N. The user initially calculated power as 325W but confused the variables for time and speed. The correct formula for work done is W = F × d, where F is the force and d is the distance. To find the necessary voltage, the user needs to clarify the power calculation and ensure they are using the correct units for time and speed. Accurate calculations are essential for determining the required voltage for the motor to perform the task effectively.
PC22
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I am working on a timelaps project so I need my motor to move very slowley, the motor I am using has a max voltage of 24V and a stall current of 1 Amp

The motor I want to use is on this link:
http://www.dynamicperception.com/EZ-Swap-DC-Motor-p/dp-dcm.htm

This motor will need to lift vertically 117N (12kg) of load to a height of1.3m (1300mm) in 60 mins (3600s) at a constant speed.

I need to find out the work done by the motor and convert it into Volts?

so far I have:

P=W/T

W=117N

T=0.36m/s

So: P=117/0.36 =325W I then times this by the time (3600s) to get the work done 1170000J

Is this correct ?
Can some out tell me how many volts this is ?

Any help would really be appreciated
 
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PC22 said:
This motor will need to lift vertically 117N (12kg) of load to a height of1.3m (1300mm) in 60 mins (3600s) at a constant speed.

I need to find out the work done by the motor and convert it into Volts?

so far I have:

P=W/T

W=117N

T=0.36m/s

So: P=117/0.36 =325W I then times this by the time (3600s) to get the work done 1170000J

Is this correct ?
That's incorrect.The work done can be found by W=F.d

Why did you write T as m/s?Isn't that the time taken(s)?or is it the constant speed given in the question?
And the W is not the force.Power =Work/time taken.
 
Care to help me work this out, please?
 
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