How much current flows through the bar?

  • Thread starter Thread starter MrDMD83
  • Start date Start date
  • Tags Tags
    Current
AI Thread Summary
The discussion centers on calculating the current flowing through an aluminum rod sliding down tilted conducting rails in a vertical magnetic field. Given the angle of the rails at 30.0°, the magnetic field strength of 0.053 T, and the rod's mass of 0.20 kg and length of 1.6 m, participants are exploring the application of the formula F=ILBsin(x). The rod moves at a constant velocity, indicating that the forces acting on it are balanced. The focus is on determining the current based on these parameters. The conversation emphasizes the relationship between magnetic fields, motion, and induced current in conductive materials.
MrDMD83
Messages
25
Reaction score
0
The two conducting rails in the drawing are tilted upwards so they make an angle of 30.0° with respect to the ground. The vertical magnetic field has a magnitude of 0.053 T. The 0.20 kg aluminum rod (length = 1.6 m) slides without friction down the rails at a constant velocity. How much current flows through the bar?
 
Physics news on Phys.org
MrDMD83 said:
The two conducting rails in the drawing are tilted upwards so they make an angle of 30.0° with respect to the ground. The vertical magnetic field has a magnitude of 0.053 T. The 0.20 kg aluminum rod (length = 1.6 m) slides without friction down the rails at a constant velocity. How much current flows through the bar?

What have you tried so far?
 
F=ILBsin(x)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top