How Much Energy is Needed to Transform Ice into Water and Steam?

  • Thread starter Thread starter physics1234
  • Start date Start date
  • Tags Tags
    Ice Steam Water
AI Thread Summary
To calculate the energy needed to transform a 55 g ice cube at 0°C into water and steam, the process involves three stages: melting the ice, heating the water, and vaporizing the steam. The correct approach requires using the latent heat of fusion for the melting phase, the specific heat capacity for heating the water, and the latent heat of vaporization for converting water to steam. The calculations should account for the full 55 g of ice melting and then heating the resulting water from 0°C to 100°C before vaporizing 15 g of that water. The initial calculations provided were incorrect due to not fully considering all phases of the transformation. Accurate energy calculations are essential for understanding phase changes in thermodynamics.
physics1234
Messages
21
Reaction score
0
A 55 g ice cube at 0°C is heated until 40 g has become water at 100°C and 15 g has become steam at 100°C. How much energy was added to accomplish the transformation?

I tried using Q=mL for each change and adding them together.

Q=.055(3.33x10^5)
Q=18315

then

Q=.015(2.26x10^6)
Q=33900

18315+33900= 52215 which is not the correct answer.
 
Physics news on Phys.org
You have 55g melting (latent heat of fusion) and 55g warming from 0° C to 100° C and then 15g vaporizing (latent heat of vaporization).
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Calorimetry: Finding mass of ice, water, steam left
Replies
1
Views
4K
How much ice to cool down this water?
Replies
17
Views
5K
Heat Transfer. Ice and steam in a container (easy)
Replies
2
Views
4K
Thermodynamics: Steam is added to an ice cube
Replies
16
Views
3K
Calculate the Mass of Ice cubes needed to cool a soft drink
Replies
10
Views
3K
Thermodynamics (final temperature, ice mixed with steam)
Replies
3
Views
9K
How Much Steam Is Needed to Heat Water from 24°C to 90°C?
Replies
1
Views
3K
Mixing water with steam, find equilibrim
Replies
14
Views
3K
Equilibrium temperature of some ice and steam
Replies
9
Views
4K
Solving Heat Transfer Problem with Melting Ice Cube
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top