How Much Force Compresses a Spring Between Two Crates on a Frictionless Surface?

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The discussion focuses on calculating the applied force and the spring force between two crates on a frictionless surface. Given the masses of the crates (640 kg and 490 kg) and the spring constant (8.1 kN/m), the spring compresses 5.1 cm, leading to specific equations for force and acceleration. The applied force can be determined using the total mass of the crates and their acceleration. The smaller crate experiences a restoring force from the spring, calculated as kx, which also relates to its acceleration. Ultimately, the calculations confirm the dynamics of the system and the forces acting on each mass.
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Two large crates, with masses 640 kg and 490 kg, are connected by a stiff, massless spring(k= 8.1 kN/m) and propelled along an essentially frictionless, level factory floor by a force applied horizontally to the more massive crate. If the spring compresses 5.1 cm from its equilibrium length, what is the applied force?
 
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What force does the spring exert? What forces act on the smaller mass? What's its acceleration?
 
Determine acceleration of the two masses (Applied force/Total mass). This will be the acceleration of each mass. Consider the smaller mass alone. Force acting on it is due to the restoring force of the spring, which is equal to kx. Write equation : Force = mass x acceleration for the smaller mass (acceleration a is in terms of the applied force F). Solve for F.
 
Vijay Bhatnagar said:
Determine acceleration of the two masses (Applied force/Total mass). This will be the acceleration of each mass. Consider the smaller mass alone. Force acting on it is due to the restoring force of the spring, which is equal to kx. Write equation : Force = mass x acceleration for the smaller mass (acceleration a is in terms of the applied force F). Solve for F.

thanks man i got the answer.
 
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