How Much Force Does Water Apply to a Sandbag Dropped from a Hot-Air Balloon?

AI Thread Summary
A sandbag weighing 2.50 kg is dropped from a hot-air balloon at 315 m above a lake and comes to rest 4.50 m below the surface. The initial velocity of the sandbag upon impact with the water can be calculated using gravitational acceleration, resulting in a velocity of approximately 61.31 m/s. To determine the force applied by the water on the sandbag, a conservation of energy approach is suggested as a more straightforward method than calculating time. The discussion emphasizes the importance of understanding the forces at play during the sandbag's descent and subsequent stop in the water. The conversation highlights the application of physics principles to solve real-world problems.
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At an altitude of 315 m above a lake, a hot-air balloon pilot drops a 2.50 kg sandbag. If the bag comes to a stop 4.50 m below the surface of the lake, what force was applied by the water on it?

Mass:2.50kg
velocity: 2.50kg*9.81m/s=61.31?

I can't remember how to figure out what the time would be?
 
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It's easier to use a conservation of energy method. So try that instead
 
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