How Much Force Must a Painter Apply to a Pulley System to Ascend?

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To determine the force a painter must apply to ascend using a pulley system, one must consider the combined mass of the painter and chair, which totals 80 kg. The equation provided, ((Ms - Mm)/(Ms + Mm)) * X = 0.2, can be used to calculate the necessary force, where X represents the force exerted by the painter. It's important to factor in gravitational acceleration (g) when analyzing the forces acting on the system. The painter's upward acceleration of 0.2 m/s requires careful consideration of all forces involved, including the tension in the rope. Understanding these dynamics is crucial for solving the problem accurately.
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this is a problem i have gotten on my homework, but this problem is giving me a bit of trouble does anyone know the best way to approch it? i was using ((Ms - Mm)/(Ms+Mm))* X = 0.2
X being the force he must pull down on

A house painter uses the chair and pulley arrangement of the figure to lift himself up the side of a house. The painter's mass is 70 kg and the chair's mass is 10 kg. With what force must he pull down on the rope in order to accelerate upward at .2 m/s
 
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been trying to work on this, i was wondering should g be a factor in the equation?
 
Since you did not include the figure, I can only make a guess as to the problem. I assume the painter is pulling himself up via a pulley and rope.

As always, identify all the forces acting on the "painter + chair" (treat them as a unit). Note that the painter pulls down on one end of the rope, but both ends of the rope pull up on him.

You may find this discussion helpful: https://www.physicsforums.com/showthread.php?t=46892
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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