How Much Force Stops a Pole Vaulter?

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The discussion centers on calculating the force exerted on a 58kg pole vaulter who falls from a height of 5.3m and comes to rest in 0.38 seconds upon landing on a foam rubber pad. The initial calculations incorrectly assumed the acceleration without first determining the landing velocity. The correct approach involves finding the velocity at impact, which serves as the initial velocity for calculating deceleration. After determining the retardation, the force can be calculated using Newton's second law. Accurate calculations are crucial for understanding the dynamics of the pole vaulter's landing.
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Homework Statement


a 58kg pole vaulter falls from rest from a height of 5.3m onto a foam rubber pad. the pole vaulter comes to rest 0.38 seconds after landing on the pad

Calculate the constant force exerted on the pole vaulter due to the collision. Answer in N


Homework Equations



d = Vi(t) + (1/2)(a)(t²)
Vf = Vi + (a)(t)

The Attempt at a Solution



d = Vi(t) + (1/2)(a)(t²)
5.3 = 0 + (1/2)(a)(.38²)
73.4 m/s² = a

Vf = Vi + (a)(t)
Vf = 0 + (73.4)(.38)
Vf = 27.89 m/s
 
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d = Vi(t) + (1/2)(a)(t²)
5.3 = 0 + (1/2)(a)(.38²)
73.4 m/s² = a
This is wrong. You have to find the velocity with which he lands on the rubber pad. That is his initial vlocity. And his final velocity is zero..Time is given. Find the retardation and hence the force.
 
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