How Much Force to Keep a 1390 kg Car from Sliding Back on a 17.5° Hill?

  • Thread starter Thread starter tatiana
  • Start date Start date
  • Tags Tags
    Forces Friction
AI Thread Summary
To prevent a 1390 kg car from sliding back on a 17.5° hill, a force of 4096.20 N is required, calculated using the formula F=mg(sinθ). The discussion clarifies that the force needed is not greater than the car's weight, which is determined by the equation mg. It emphasizes that weight is a product of mass and gravitational acceleration, making it essential to use consistent units when comparing forces. The conversation highlights the importance of understanding the relationship between force, weight, and angle in physics problems. Overall, the calculations and concepts discussed are accurate and relevant to the scenario presented.
tatiana
Messages
43
Reaction score
1
The question is saying that in a city, most roads are 17.5 degrees to the horizontal. They want to know how much force is needed to keep at 1390 kg car from sliding back on teh hill?

Solution:
I first drew a FBD and then broke the diagram into components F, the force.
After i didi that i used F=mg(sinθ) and plugged everything in and got 4096.20N

My question is not only am i doing this right? But can the force that you solve for be greather than the actual weight of teh car?
 
Physics news on Phys.org
Looks like moondawg is in your same class:
https://www.physicsforums.com/showthread.php?t=440104

Yes you are right. The force is not greater than the weight. Remember, the weight is mg, not just m. You cannot say if the force is greater or less than the mass since they are different units and cannot be compared.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

How is centripetal force involved here? (charged mass sliding down a conducting hemisphere)
Replies
31
Views
1K
How is the minimum work needed to push a car up an inclined plane calculated?
Replies
4
Views
3K
Calculating acceleration from the coefficient of kinetic friction
Replies
48
Views
8K
How do I draw a FBD for centripetal force
Replies
6
Views
4K
How Does Speed Affect Normal Force at the Crest of a Hill?
Replies
1
Views
3K
Cars Collide on a Hill, Conservation of Momentum
Replies
7
Views
2K
A father spins his child on a cart
Replies
10
Views
2K
How Do You Calculate the Force Needed to Prevent a Block from Sliding on a Wall?
Replies
1
Views
2K
Minimum spring force required to keep a car level
Replies
34
Views
5K
Forces and Hills: Calculating Force of 1967 Corvette on a 17.5° incline
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top