How Much Mass is Needed to Prevent the Wheel from Rotating?

AI Thread Summary
To prevent the wheel from rotating, the sum of the torques must equal zero, which involves balancing the moments of inertia of the system. The equation m1r1^2 + m2r2^2 = 0 is used to relate the masses and their respective distances from the axis of rotation. A calculation shows that the mass M needed to achieve this balance is 39 kg, correcting an earlier miscalculation of 201 kg. The problem emphasizes the importance of understanding rotational dynamics and torque in mechanical systems. Proper application of these principles leads to accurate solutions in physics problems involving rotational motion.
hey123a
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Homework Statement


A large wheel has a radius of 7.1 m. A rope is wrapped around the edge of the wheel and a 7.6 kg box hangs from the rope. A smaller disk of radius 1.38 m is attached to the wheel. A rope is wrapped around the edge of the disk as shown. An axis of rotation passes through the center of the wheel-disk system. What is the value of the mass M that will prevent the wheel from rotating?


Homework Equations





The Attempt at a Solution


all moments of inertia should equal zero so
m1r1^2 + m2r2^2 = 0
m1 = -m2r2^2/r1^2
m1 = -(7.6)(7.1)^2/1.38^3
m1 = 201

answer is actually 39kg
 
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hey123a said:

Homework Statement


A large wheel has a radius of 7.1 m. A rope is wrapped around the edge of the wheel and a 7.6 kg box hangs from the rope. A smaller disk of radius 1.38 m is attached to the wheel. A rope is wrapped around the edge of the disk as shown. An axis of rotation passes through the center of the wheel-disk system. What is the value of the mass M that will prevent the wheel from rotating?


Homework Equations





The Attempt at a Solution


all moments of inertia should equal zero so
m1r1^2 + m2r2^2 = 0
[/QUOTE]

The torques have to sum up to zero.

ehild
 
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