For the circuit of Figure 30-19, assume that EMF= 14.0 V, R = 5.40 , and L = 5.00 H. The battery is connected at time t = 0. Picture: http://www.webassign.net/hrw/hrw7_30-19.gif Okay i know there is a simple formula to find the: (a) How much energy is delivered by the battery during the first 2.00 s? J but i don't know where it is, anyone know it? Also I tried part (b) and got it wrong for some reason: How much of this energy is stored in the magnetic field of the inductor? wrong check mark J I used: V = iR. Ub = .5L*i^2; i = 14/5.40 = 2.59 Amps Ub = .5*5.00*2.59^2 = 16.77 but they didn't like that at all, any ideas? thanks.