How Much Potential Energy Does Water at the Top of a 200ft Waterfall Possess?

AI Thread Summary
The discussion centers on calculating the gravitational potential energy (PE) of 4000 pounds of water at the top of a 200-foot waterfall. The formula PE = mgh is debated, with participants clarifying that pounds are a unit of force, not mass, leading to confusion over the use of slugs. The correct calculation for potential energy is determined to be PE = (4000 lb)(200 ft) = 800,000 lb*ft. Participants also note that the kinetic energy (KE) of the water at the bottom of the fall equals its potential energy at the top. The importance of using consistent units in calculations is emphasized throughout the discussion.
Windseaker
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1.4000lb of water are at the top of a 200ft. waterfall ready to fall. What is the amount of gravitational potential energy?



2. PE=mg(change in height)



3. PE= (4000lb)(1slug/32lb)(200ft)
PE= 25,000lb*ft
I think somethings missing
 
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Hello Windseaker,

I've always hated working any system that has units of slugs. http://www.websmileys.com/sm/aliens/hae48.gif

No seriously though,

You might want to look again at your question and equation carefully. Are pounds units of mass or of force? :wink: (hint: the units of PE in this system should be a dead giveaway on what went wrong.)
 
Im haveing the basic problem of understanding the use of gravity in Lb./ft2 or slugs "itself" here. I thought it was a basic problem to understand it with. Is there any American unit help here?

(4000lb.=m)/(32 ft/s2=g)= 125slugs ?? 1slug= lb.sec2/ft

is this right?
 
Windseaker said:
Im haveing the basic problem of understanding the use of gravity in Lb./ft2 or slugs "itself" here. I thought it was a basic problem to understand it with. Is there any American unit help here?

(4000lb.=m)/(32 ft/s2=g)= 125slugs ?? 1slug= lb.sec2/ft

is this right?

Yes, I believe you're right! (except for the '=m' part)

But let me give you a hint that might make the problem easier. In this problem, you don't need to bring slugs into it.

You've already stated that PE = mgh. We know from Newton's second law that F = ma. Gravitationally speaking, this becomes F = mg. Therefore gravitational PE = Fh.

And by the way, in case you didn't know,
Slugs are units of mass.
Pounds are units of force.
 
PE = Fh
Your saying that
PE = (4000lb)(200ft)
=800,000lb(ft) ?

what happened to g

I was hopping to see how everything cancels out!

sorry , I just missed this, is this right?

if so can you help me understand Kinetic Energy of this problem (then water hits) as well??
 
Last edited:
OK, I believe this is right. except---ft*lbs

PE = mgh, F = ma, F = mg, Therefore gravitational PE = Fh

PE = Fh

PE = (4000lb)(200ft)
=800,000lb(ft) ?---------------800,000ft*lbs.

ft*lbs is a English unit for Energy and does not need to be converted to joules!

The KE=PE(when water is at the bottom or impact)!

English units are important too, unfortunately, but very real.

Anyone what to double check me here? :mellow:
 
'Sounds good to me. :approve:
 
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