The discussion revolves around a physics problem involving a rope pulling a 1200 Kg car with an upward acceleration of 0.8 m/s². Participants are exploring the concept of tension in the rope and how it relates to the forces acting on the car.
Participants have engaged in a back-and-forth regarding the forces at play, with some clarifying the roles of tension and weight. Guidance has been provided on the need to consider the direction of forces and the implications for calculating tension.
There is an emphasis on understanding the algebraic sum of forces and the importance of sign conventions in the calculations. Participants are navigating through the assumptions related to the forces acting on the car.
That's the net force. The net force is the algebraic sum of all the forces acting on the car. What are the forces acting on the car?Ryuk1990 said:Homework Statement
A rope is pulling up a 1200 Kg car. The upwards acceleration is 0.8 m/s2. How much tension should the rope be able to withstand?
Homework Equations
Net force is equal to mass x acceleration.
The Attempt at a Solution
So would it just be 1200 Kg x 0.8 m/s2 which is 960 Newtons?
PhanthomJay said:That's the net force. The net force is the algebraic sum of all the forces acting on the car. What are the forces acting on the car?
Gravity is one force acting down on the car (it's weight). The other force is the contact force (which perhaps you are calling the normal force) which is actually the ___?____ force in the ____?___ which acts ______________(up/down, choose one).Ryuk1990 said:The normal force and gravity?
You have already calculated the net (resultant) force. It is equal to 960 N. The net force always acts in the direction of the acceleration, thus, the net force of 960 N acts up. The net force on the car is comprised of 2 forces: the weight of the car, acting down, and the rope tension, which must act up (since the net force is up, the tension force must be greater than the weight force). So you have the tension force acting up, and the weight force acting down, and their net total (algebraic sum) must be 960N .. So the tension force is ?Ryuk1990 said:The net force in the system which acts up?
PhanthomJay said:You have already calculated the net (resultant) force. It is equal to 960 N. The net force always acts in the direction of the acceleration, thus, the net force of 960 N acts up. The net force on the car is comprised of 2 forces: the weight of the car, acting down, and the rope tension, which must act up (since the net force is up, the tension force must be greater than the weight force). So you have the tension force acting up, and the weight force acting down, and their net total (algebraic sum) must be 960N .. So the tension force is ?