How Much Torque to Spin a Disk at 30,000 RPM?

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To spin a disk with a mass of 54.3 grams at 30,000 RPM, the required torque depends on overcoming initial inertia, friction, and air resistance. In a frictionless scenario, no torque is needed to maintain constant speed, but torque is necessary to accelerate the disk from rest. The discussion emphasizes the importance of specifying units for mass and understanding the context of torque application. The formula for torque typically involves factors such as moment of inertia and angular acceleration. Proper calculations and considerations of friction and resistance are essential for accurate torque determination.
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Hi, I'm new to this forum so I'm not exactly sure if I'm posting in the right place. But I have a question about torque.

Okay so, how much torque would a motor need to supply to be able to spin a disk with a mass of 54.3 g at 30,000 RPM?

If you could also provide and explain the formula for determining torque that would be great.

Thanks!
 
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bcjirvin said:
Hi, I'm new to this forum so I'm not exactly sure if I'm posting in the right place. But I have a question about torque.

Okay so, how much torque would a motor need to supply to be able to spin a disk with a mass of 54.3 at 30,000 RPM?

If you could also provide and explain the formula for determining torque that would be great.

Thanks!

Welcome to the PF.

What is the context of the question? It takes no torque to spin a disk on frictionless bearings at a constant RPM. The torque would be needed to spin the disk up from zero to final speed, and to overcome bearing friction and any air resistance involved.

Also you need units on the mass that you supplied...
 
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