How Much Water Does a 115578 Ton Cargoship Displace?

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The discussion centers on calculating the volume of water displaced by a 115,578-ton cargo ship in saltwater with a density of 1,030 kg/m³. The group converted the ship's weight to kilograms, resulting in 115,578,000 kg. They then divided this weight by the water's density, yielding a volume of approximately 112,211.65 m³. However, it was pointed out that the answer should reflect the correct terminology, as it represents volume, not area, and should be rounded to four significant figures, resulting in 112,200 m³. Accurate calculations and terminology are crucial in solving such physics problems.
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Homework Statement


I've been working as part of a study group, but I doubt that the result we reached in class is correct, so would someone check our work?

The problem statement: A cargoship weighs in at 115578 ton and lies still in the ocean. The density of the saltwater is given at 1030 kg/m3
what is the area of the water displaced by the weight of the cargoship?

Homework Equations



This is the part where I'm somewhat uncertain, since we simply used math tools. This is also the area in which any help would be extremely usefull


The Attempt at a Solution



The attempt at this was:

converting the ships weight to kilograms: 115578 ton = 115578000 kg

Then dividing the weight by the density:
115578000kg/1030 (kg/m3) = 112211,65 m3
 
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correct, except you mean the VOLUME of water displaced, not AREA
And you have too many decimal places in you answer, you only know the density to an accuracy of four significant figures so your answer can only be that accurate.
eg 112200m^3
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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