How much work and how much force do we use in pushing a box

  • Thread starter Thread starter mmoadi
  • Start date Start date
  • Tags Tags
    Box Force Work
AI Thread Summary
The discussion focuses on calculating the work done and the force required to pull a wooden block with a mass of 1 kg over a distance of 1 m on a rough surface with a coefficient of friction of 0.1. The frictional force is determined to be 0.98 N, leading to a calculated work of 0.98 J. The strength used in pulling the block is derived using the equation W = F∆xcosθ, resulting in a force of approximately 1.13 N. The calculations are confirmed to be accurate, with a minor adjustment noted in the force value. Overall, the problem illustrates the application of physics equations to determine work and force in a practical scenario.
mmoadi
Messages
149
Reaction score
0

Homework Statement



How much work do we do when we pull a wooden block with a mass m = 1 kg and we displace it for ∆x= 1 m. The object is being pulled on a rough surface with a coefficient of friction µ_k = 0.1. We are pulling the object with a string; the angle between the string and the surface is 30º. How much strength are we using when pulling the wooden block if the block is moving at 1 m/s at all times.

Homework Equations



F_k= µ_kN
F=ma
N= mg-Fsinθ
W= F∆x

The Attempt at a Solution



1) How much work is done:

F_k= µ_kN → F_k= µ_kmg= 0.98N
W= F∆x= 0.98J

2) How much strenght are we using:

W= F∆xcosθ
F= W/ ∆xcosθ= 1.12N
 
Physics news on Phys.org
Those look good. You might check 2 again - for .98/cos(30) I get 1.13 instead of 1.12.
 
Yes, you are right, it is 1.13 N.

Thank you for your help! Have a nice day!
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top