How much work is done by gravity on an object sliding down an inclined plane?

AI Thread Summary
The discussion centers on calculating the work done by gravity on a 10.0 kg object sliding down a 30.0° inclined plane over a distance of 2.00 m. It emphasizes that gravity is a conservative force, meaning only the change in vertical height affects the work done, not the distance traveled along the slope. The coefficient of kinetic friction is noted as 0.200, which may influence the overall dynamics but is not directly relevant to the work done by gravity. The gravitational acceleration is given as g = 10.0 m/s². Understanding these principles is essential for accurately determining the work done by gravity in this scenario.
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An object of mass 10.0 kg is released from the top of an inclined plane which makes an angle of inclination of 30.0� with the horizontal. The object slides along the inclined plane. The questions refer to the instant when the object has traveled through a distance of 2.00 m measured along the slope. The coefficient of kinetic friction between the mass and the surface is 0.200. Use g = 10.0 m/s2. How much work is done by gravity?
 
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Can anyone please help me out?
 
gravity is a conservative force which means that only the change in vertical height (not distance travelled) matters when measuring work done by gravity.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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