How Much Work Is Done When Pulling a Sled at an Angle?

AI Thread Summary
To calculate the work done when pulling a sled at an angle, the formula W = f x s x cos(θ) is used, where f is the force, s is the distance, and θ is the angle. In this case, the force is 74 N, the distance is 27 m, and the angle is 26°. The initial calculation of work done resulted in 1292.54, but this was deemed incorrect. Clarification is needed on whether the angle should be in degrees or radians, as well as the sled's displacement context. Understanding these factors is crucial for accurately determining the work done on the sled.
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Homework Statement


A sled is pulled across the barren winter landscape at an angle of 26.0° from the ground with a force of 74 N. If the sled is pulled over a distance of 27 m, how much work was done on the sled? Round your answer to two decimals

Homework Equations


W = f x s x Cos

The Attempt at a Solution


I calculated the force , 74, times 27 to get 1998. Then I multiplied 1998 by the cosine of 26 to get 1292.54 but it says that it's wrong. My teacher told me to think about the displacements but I don't get his meaning.
 
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joesmith273 said:
Then I multiplied 1998 by the cosine of 26 to get 1292.54

You multiplied by cosine of 26 what ? Radians or degrees?
 
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joesmith273 said:

Homework Statement


A sled is pulled across the barren winter landscape at an angle of 26.0° from the ground with a force of 74 N. If the sled is pulled over a distance of 27 m, how much work was done on the sled? Round your answer to two decimals

Homework Equations


W = f x s x Cos

The Attempt at a Solution


I calculated the force , 74, times 27 to get 1998. Then I multiplied 1998 by the cosine of 26 to get 1292.54 but it says that it's wrong. My teacher told me to think about the displacements but I don't get his meaning.
Is the sled being pulled over flat ground or up an incline?
 
Your method looks fine but see post #2.

Your teachers is talking about a common error but it's one that you didn't make.
 
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