How much work was done on the mass?

  • Thread starter Thread starter OstralyanPain
  • Start date Start date
  • Tags Tags
    Mass Work
Click For Summary
SUMMARY

The discussion focuses on calculating the final velocity and work done on a 1.20 x10^3-kg block accelerated by a 2.20 x10^3-N force over a distance of 50.0 meters on a frictionless surface. The correct formula for work, W = Fd, was applied, but the arithmetic was incorrect, leading to a miscalculation of work done. The correct work done is 1.1 x 10^5 Joules, not 0.11 Nm. For finding the final velocity, participants suggested using kinematics or relating work done to kinetic energy.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with the work-energy principle
  • Basic knowledge of kinematics equations
  • Ability to perform calculations with scientific notation
NEXT STEPS
  • Review the work-energy theorem and its applications
  • Practice solving problems using kinematics equations
  • Learn how to convert between different units of energy
  • Explore the concept of frictionless surfaces in physics
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in motion.

OstralyanPain
Messages
1
Reaction score
0

Homework Statement


A 1.20 x10^3-kg block starting from rest is accelerated by a 2.20x10^3-N force for a distance of 50.0 meters along a horizontal frictionless surface.

a. What is the final velocity of the mass?

b. How much work was done on the mass?

I have no clue how to get A but for B i just Used W=Fd and got 2.20x10^3-N * 50m =
0.11 (Nm)

Can someone confirm my answer to B and help me with A?

Thanks.
 
Physics news on Phys.org
OstralyanPain said:
I have no clue how to get A but for B i just Used W=Fd and got 2.20x10^3-N * 50m =
0.11 (Nm)
Correct formula, but redo that arithmetic. (Keep better track of the exponents.)

For A, either find the acceleration and use kinematics or use the result of part B and relate the work done to the kinetic energy.
 

Similar threads

Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
13
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 47 ·
2
Replies
47
Views
4K
Replies
18
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K