- #1
wakko101
- 68
- 0
electric potential...again.
So, I've still got my two infinite lines of charge that run parallel to the x-axis running along the lines x = a and x = -a and with charge density + and - lambda respectively.
I've figured out that using the origin as my reference point allows me to integrate the electric field of my lines from a to the point in question (r). However, because the field goes like 1/r, we end up with a ln of something in the potential. For the line that's positive a away from the x axis, there's no problem. But, for the line that runs along x = -a, how can I integrate? should I be integrating from a to r again, or from -a to r. The problem with the latter is that you can't have the natural logarithm of a negative number.
I would REALLY appreciate any advice. I'm a little desperate...
Cheers,
W. =)
So, I've still got my two infinite lines of charge that run parallel to the x-axis running along the lines x = a and x = -a and with charge density + and - lambda respectively.
I've figured out that using the origin as my reference point allows me to integrate the electric field of my lines from a to the point in question (r). However, because the field goes like 1/r, we end up with a ln of something in the potential. For the line that's positive a away from the x axis, there's no problem. But, for the line that runs along x = -a, how can I integrate? should I be integrating from a to r again, or from -a to r. The problem with the latter is that you can't have the natural logarithm of a negative number.
I would REALLY appreciate any advice. I'm a little desperate...
Cheers,
W. =)