How Small Can the Iceberg Get Before the Polar Bear Gets Wet Feet?

AI Thread Summary
The discussion centers on calculating the minimum volume of an iceberg that can support a 520 kg polar bear without it getting wet as the ice melts. The buoyant force equation is used, incorporating the densities of ice and seawater. An initial calculation yielded a volume of 4.73 m³, but the answer was deemed incorrect. Participants suggest that the full volume of the iceberg should be considered in the buoyancy force calculation, questioning whether the error stems from a textbook answer or a computer system. The conversation emphasizes the importance of accurately applying buoyancy principles to solve the problem.
CR9
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Homework Statement


A polar bear of mass 520 kg is floating on an iceberg in the ocean. As the ice melts, how small can the iceberg get before the bear gets wet feet? (The answer should be the volume of the iceberg).


Homework Equations


Buoyant Force, Fb = p(fluid)V g

From a table in my textbook, p(ice)= 920 kg/m^3 and p(sea water)= 1030 kg/m^3



The Attempt at a Solution


I did a sum of the forces in the y-direction to be zero and obtained:

Fb - W(bear) - W(ice)= 0
p(sea water)V = 520 + p(ice)V
V= 4.73 m^3

My answer is wrong... PLease help...
 
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CR9 said:

Homework Statement


A polar bear of mass 520 kg is floating on an iceberg in the ocean. As the ice melts, how small can the iceberg get before the bear gets wet feet? (The answer should be the volume of the iceberg).


Homework Equations


Buoyant Force, Fb = p(fluid)V g

From a table in my textbook, p(ice)= 920 kg/m^3 and p(sea water)= 1030 kg/m^3



The Attempt at a Solution


I did a sum of the forces in the y-direction to be zero and obtained:

Fb - W(bear) - W(ice)= 0
p(sea water)V = 520 + p(ice)V
V= 4.73 m^3

My answer is wrong... PLease help...

I like your answer!
 
I also think your answer is correct.
 
I also am getting your answer: the iceberg is just completely submerged, so you should be using its full volume in the buoyancy force calculation. Is what is telling you this is wrong an answer in the back of a textbook, or a computer problem system?
 
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