How Small Must a Bone Be to Detect a 5% Change in X-ray Imaging Intensity?

AI Thread Summary
The discussion revolves around determining the smallest diameter of a bone detectable by X-ray imaging, given a 5% change in intensity and an absorption length of 0.017 m for bone. The user attempts to apply the equation I=I0e-μx but struggles with the calculations and the concept of absorption length versus absorption coefficient. Clarifications are sought regarding the proper setup of the equation, particularly concerning dimensions and the interpretation of absorption length. The correct answer is suggested to be 1.3 mm, but confusion persists about the calculations leading to this result. The conversation highlights the complexities of applying theoretical concepts to practical imaging scenarios.
jdemps
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Homework Statement



Imagine a 10 cm thick slab of flesh. If your x-ray imager can reliably identify a 5% change in intensity from one location to another in an image, what is the smallest diameter bone you are going to be able to make detect in your x-ray image?

Absorption length of bone: 0.017 m

Homework Equations



I=I0e-μx

The Attempt at a Solution



I tried letting 0.05=e-μx letting 0.017m be μ. The correct answer is supposed to be 1.3 mm but I can't seem to get that.
 
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1. going from 1 to 0.05 is a change of 0.95. Consider going from I = 1 to I = 0.95.
2. μx must have no dimension, otherwise you can't exponentiate it. your exponent has the wrong dimension...
3. What is the definition of absorption length in your context ? I = I0 / e or I = I0 / 2 ?
 
I set it up so that 0.95=e-μx trying to let μ=1/0.017 so that x could be in meters without having units in the exponent. That did not work either when trying to solve for x. There are no explanations for these practice problems and I have only ever heard the term "absorption coefficient" not absorption length, which is why I'm confused.
 
"Did not work either" means you found 0.017 m * ln(0.95) = 0.00087 m ?

I agree the most common maeening for absorption length is length over which I = I0 / e.

It's just because your 'right' answer corresponds to 0.017 m * 2log(0.95) that I asked for this context.

I can't think of anything else to help you with at this moment (bedtime+3h)...:frown:
 
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