[tex](adsbygoogle = window.adsbygoogle || []).push({});

1^2+2^2+..+k^2=\frac{k(k+1)(k+2)}{6}

[/tex]

how to get this general result

??

i know

1+2+..+n=\frac{n(n+1)}{2}

so by that rule the sum should be

[tex]

\frac{n(n^2+1)}{2}

[/tex]

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# How they get to this formula

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