How to accurately represent motion using a vector diagram?

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The discussion focuses on accurately representing motion using a vector diagram for a duck paddling on a pond. Participants emphasize the importance of drawing vectors correctly, starting the second vector from the tip of the first. They clarify that to find total displacement, one must break vectors into their x and y components and add them accordingly. The distinction between distance and displacement is highlighted, with displacement being a vector quantity. Overall, the conversation provides guidance on vector diagram techniques and the calculation of displacement.
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The question was, "In a total time of 2.0 min, a duck on a pond paddles
22 m [36deg N of E] and then paddles another 65 m [25 deg E of S]"

a) Draw a vector diagram that represents this motion. Be sure to include
a scale and compass.

I've given a new try with this diagram. Could anyone please correct it for me?
Any advice would be greatly appreciated.

Thanks for your time.

Link to the diagram:
http://img139.imageshack.us/my.php?image=37755109ri9.jpg

p.s / To find the Total Displacement, should I use the x & y component added together
then use the inverse tan to find the angle and direction?
 
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check your methods for drawing vectors. After you draw the first vector you draw the second vector from the tip of previous one. If you do they way you drew the vectors check out... http://hyperphysics.phy-astr.gsu.edu/hbase/vect.html#veccon and the links within that web...that should help.
 
Midy1420 said:
check your methods for drawing vectors. After you draw the first vector you draw the second vector from the tip of previous one. If you do they way you drew the vectors check out... http://hyperphysics.phy-astr.gsu.edu/hbase/vect.html#veccon and the links within that web...that should help.

Thanks again Mindy,
I think I got it now!

http://img137.imageshack.us/my.php?image=21pm6.jpg

What do you think?
 
also according to your drawing you have the correct distance traveled but distance and displacement are not the same thing.

Displacement is a vector so you have to break every vector into its x and y components. you can only add x components with x components and so on.
 
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Midy1420 said:
also according to your drawing you have the correct distance traveled but distance and displacement are not the same thing.

Displacement is a vector so you have to break every vector into its x and y components. you can only add x components with x components and so on.

Ok ^^
Thank you very much!
 
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