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How to approach a simple harmonic motion problem

  1. Oct 1, 2011 #1
    This is the question:

    A massless spring with a spring constant of 0.50 N/m, has a mass of 0.7 kg on its end. The maximum speed of the end is 2.5 m/s. What is the angular frequency of the system?

    I don't know how to approach this problem at all. I just know that omega/2pi is the frequency. But, we don't even have omega. I am so stuck and confused.
     
  2. jcsd
  3. Oct 1, 2011 #2

    SammyS

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    Can you write an equation for the motion of the spring.

    Doesn't ω depend only on spring constant, k, and mass, m, both of which you know?
     
  4. Oct 1, 2011 #3
    i see, i forgot omega is the sqrt of k/m. thanks for the reply.
     
  5. Oct 1, 2011 #4
    ω is equal to .845 m/s. Divide that by 2pi to get the angular frequency and you get .1345, which is incorrect.

    Edit: Angular frequency (not frequency) is .845 m/s (the answer).

    Thanks for the help. I really do appreciate it.
     
  6. Oct 1, 2011 #5

    SammyS

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    Glad to help !
     
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