How to arrive at answer for integration question

  • Thread starter Thread starter Alexenn
  • Start date Start date
  • Tags Tags
    Integration
AI Thread Summary
To solve the integration question regarding a stone thrown upwards with an initial velocity of 20 m/s and accelerated downwards by gravity at 10 m/s², the antiderivative of the acceleration must be calculated. The correct approach involves integrating the acceleration function, which is -10 m/s², leading to the equation v(t) = -10t + C. The integration process does not require including units in the integral. Clarification on the signs and units is essential for arriving at the correct solution. Understanding these concepts allows for progress in solving the problem.
Alexenn
Messages
3
Reaction score
0
Firstly, I am sorry if this is the wrong section (I really didn't know what each section meant, but I posted here since I am beginner)

Homework Statement



A stone is thrown up into the air at 20m/s is accelerated constantly downwards by gravity at about 10m/s2

Find the anti derivative of the acceleration

Note: I am not solving for C

Homework Equations


The Attempt at a Solution



The antiderivative of 20m/s is 10m/s2
and the antiderivate of -10m/s is -5m/s2

Neither of those match up to the answer, so I'm not sure how to arrive at the answer.

The answer in the book is v= -10t + c

Thankyou
 
Last edited:
Physics news on Phys.org
If you have a = 10 then you need to find \int 10\ dt. There's no need to include units in your integral.
 
Ah, thank you very much. Can finally get on with work! =)
 
JHamm said:
If you have a = 10 then you need to find \int 10\ dt. There's no need to include units in your integral.
That should be a = -10. Of course, the units are m/s2 .
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top