How to Avoid Common Mistakes in Solving Forces Problems?

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To solve the forces problem, the resultant force was calculated using vector components, resulting in a magnitude of approximately 739.94N and a direction of 25.82° from north. The confusion arose regarding the use of sine and cosine functions, which was clarified by drawing the vectors on an x-y plot. A significant error was identified when the calculator was set to radians instead of degrees, leading to incorrect results. This highlights the importance of ensuring calculator settings are correct before performing calculations. Checking settings is a common mistake that can impact exam performance.
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Homework Statement


A particles is under the influence of two forces, 500N at 50° from north and 350N at 350° from north. Find the magnitude and direction of the resultant pull on the particle.

Homework Equations



?

The Attempt at a Solution


<br /> x=500cos40-350cos80\\<br /> x=322.25N\\<br /> y=500sin40+350cos10\\<br /> y=666.08N \\<br /> <br /> \sqrt{322.25^2 + 666.08^2}=739.94N \\<br /> arctan(322.25/666.08)=25.82° from north. \\<br />
I am a bit confused on when to use cos or sin. The above is how a classmate pursaded me to change it to but on my first go I had
<br /> x=500cos40-350sin10 \\<br /> <br /> y=500sin40+350cos10 \\<br />
 
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Draw the vectors on an x-y plot (+y = North). It should be obvious from that.
 
rude man said:
Draw the vectors on an x-y plot (+y = North). It should be obvious from that.

Thanks for your reply. I have already done that and the figure and direction obtained seem correct but I don't know for sure and if my method is correct.

EDIT: Sorry just realized my mistake. They are both the same but doing it a different way, my calculator was set on radians instead of degrees and that is why I was getting different figure to earlier :redface: sorry.
 
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FaraDazed said:
..., my calculator was set on radians instead of degrees ...
A very common mistake. Remember to check the setting whenever you have an exam :smile:
 
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