How to Calculate Capacitance for Two Slanted Conducting Plates?

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Homework Help Overview

The problem involves calculating the capacitance of two conducting plates that are oriented at an angle to each other. The plates have specific dimensions, and the setup includes considerations of distance and angle between the plates.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of a differential strip approach to derive capacitance, questioning the definition and calculation of the distance variable d'. There is also a focus on the accuracy of the numerical values provided in the problem statement.

Discussion Status

The discussion is ongoing with participants exploring different interpretations of the problem. Some guidance has been offered regarding the setup of the capacitance calculation, but there is no explicit consensus on the correct approach or values.

Contextual Notes

Participants note discrepancies in the numerical values related to the distances between the plates, which may affect the calculations. There is a specific mention of the angles and distances that need clarification.

blackblanx
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Homework Statement



Determine the capacitance of two conducting plates facing each other at an angle as shown (in link) . Plate A and B have dimensions of 10x20 cm and 10x (20sec30) (angles in degrees)

Homework Equations


C=( [tex]\epsilon[/tex] A)/d


The Attempt at a Solution


not quite sure can someone help me get the ball rolling or the floor moving
 

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If you take one strip of the plate of width dx and length L.
The capacity of that strip is given by
ΔC = εο*L*dx/(d + d')
From the figure write down d' in terms of x and θ.
Find the integration to get the capacitance C.
 
What are you using for d' ?
 
blackblanx said:
What are you using for d' ?
d' is the variance distance of the slanted plate from the horizontal line.
In the problem, numerical values are not correct.
One end of the slanted plate is 1 mm from the top plate,. And the other end is 0.1 mm from the top plate. So tan θ = 0.9 mm/0.1 mm which is not equal to tan(30)
 

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