How to Calculate Equilibrium Pressures in a Chemical Reaction?

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To calculate the equilibrium pressures for the reaction A + B → 2C, start with initial pressures of Pa = 3 atm and Pb = 2 atm. Given that 70% of B reacts, this means 0.7 moles of B are consumed, leading to a decrease of 1.4 atm in Pb. Consequently, the changes in pressures are -1.4 atm for Pb and +2.8 atm for Pc, resulting in Pb = 0.6 atm and Pc = 2.8 atm at equilibrium. The final pressure for A, Pa, will be 3 atm - 0.7 atm = 2.3 atm. The equilibrium constant can then be calculated using the equilibrium pressures.
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Reacton between the substances is A+B--> 2C where Pa=3 atm,Pb=2 atm.The reaction moves to the right until 70 percent of B has reacted and we have the equilibrum.FFind Pa,Pb,Pc and the constant of equilibrum

Pa Pb Pc

So in the beginning 3 2 0

The change - x -x +2x How do I find Pa ,Pb and Pc here?
 
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Elaia06 said:
Reacton between the substances is A+B--> 2C where Pa=3 atm,Pb=2 atm.The reaction moves to the right until 70 percent of B has reacted and we have the equilibrum.FFind Pa,Pb,Pc and the constant of equilibrum

Pa Pb Pc

So in the beginning 3 2 0

The change - x -x +2x How do I find Pa ,Pb and Pc here?

You are told that 70% of B has reacted...
 
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