How to Calculate Heat Loss Per Hour Through a Glass Window Pane?

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Homework Help Overview

The discussion revolves around calculating heat loss through a glass window pane, with specific dimensions and temperature conditions provided. The subject area includes thermodynamics and heat transfer principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between heat loss, window area, and temperature difference. Questions arise regarding the relevant equations and concepts, such as the analogy to electrical resistance.

Discussion Status

Some participants have offered insights into how heat loss is expected to scale with area and temperature difference. There is ongoing exploration of the appropriate equations and constants involved in the calculations.

Contextual Notes

Participants note uncertainty regarding specific equations and constants, as well as the implications of the data provided for the material properties.

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Homework Statement



A glass window pane is 2.7 m high, 2.4 m wide and 2 mm thick. The temperature at the inner surface of the glass is and at the outer surface 4°C. How much heat is lost each hour through the window?



The Attempt at a Solution



I have the stats on the glass like specific heat ect.

Im not quite sure what equations to use to solve this
 
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How would you expect the power lost to depend on the area of the window and the temperature difference?

Do you know the equation for electrical resistance of a material? How is this similar?
 
no, I am not quite sure what that equation is.
 
You can work it out simply.

You expect the heat loss to go up with more area - double the area = double the heat loss.
And you expect it be proportional to the temperature difference, double the temperature difference double the heat loss.

so you have power is proprtional to area * temperature differences
or P = k A dt
where k is some constant for your material

Depending on how your data is given 'k' might be thermal conduction = bigger number is more heat lost, or thermal resistance = small number is more heat lost, so you migth have K or 1/K in the equation. You can tell from the units given for 'k'
 

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