How to Calculate Heat Lost or Gained in a Reaction?

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To calculate the heat gained or lost in the reaction between potassium hydroxide and hydrobromic acid, the heat capacity and density of the solution are essential. The temperature change from 20.1°C to 24.5°C indicates a heat transfer that can be quantified using the formula Q = mcΔT, where Q is heat, m is mass, c is specific heat capacity, and ΔT is the temperature change. Since the total volume of the solution is 41 mL, it can be converted to mass using the density of the solution. Understanding the relationship between heat, temperature change, volume, and heat capacity is crucial for solving the problem effectively.
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0.100 mol/L + 23 ml of Potassium Hydroxide is mixed with 18 ml of hydrobromic acid. Calculate the heat gained or lost by the reaction.

The initial temperature was 20.1 celcius and the final was 24.5 celcius.

i have no clue how to solve this equation. Can someone give me clues and what equation to use?
 
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The only important information you have is that 41 mL of solution is heated from 20.1 C to 24.5 C. You need the heat capacity and density of that solution (either given or make an assumption) to complete the calculation.

Do you know of a relationship between heat and temperature change, volume (mass?) and heat capacity?
 
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