How to Calculate Initial Radioactive Activity for Patient Treatment?

  • Thread starter Thread starter soul5
  • Start date Start date
  • Tags Tags
    Half life Life
AI Thread Summary
To calculate the initial radioactive activity for patient treatment, the half-life of the radioactive sample is crucial, which is given as 83.61 hours. The desired activity at the time of irradiation is 7.0 x 10^8 Bq for a duration of 24 hours. The correct approach involves using the equation T1/2 = ln2/λ to find the decay constant (λ). After determining λ, the initial activity can be calculated using the formula N = N0e^(-λt). This method ensures accurate calculations for effective patient treatment.
soul5
Messages
63
Reaction score
0

Homework Statement



Ok so I'm doing this practise problem but I have no clue what to do.

"A radioactive sample intended for irradiation of a hospital patient is prepared
at a nearby lab. The sample has a half-life of 83.61 h. What should it's initial activity be if it's activity is to be 7.0 X 10 ^ 8 Bq when it is used to irradiate the patient for 24 h?


Homework Equations




T 1/2 = Ln2/λ

N = N0e^λt


The Attempt at a Solution



Would you just do this?


N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

?

please help
 
Physics news on Phys.org
soul5 said:
Would you just do this?


N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

?

please help


Unfortunately not, start with

T1/2 = ln2/lambda
lambda = ln2/(T1/2)

and try again. Hope this helps :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top