How to Calculate Kinetic Energy from an Internal Explosion?

AI Thread Summary
An internal explosion divides an object at rest into two pieces, with one piece having 1.6 times the mass of the other. The total energy released is 25,000 J, which is distributed between the two pieces based on their masses and velocities. The lighter piece acquires approximately 15,385 J of kinetic energy, while the heavier piece acquires about 9,615 J. The calculations involve using the relationship between mass, velocity, and kinetic energy. The final results confirm the distribution of kinetic energy between the two pieces after the explosion.
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Homework Statement



An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.6 times the mass of the other. If 25000 J is released in the explosion, how much kinetic energy does each piece acquire?

Homework Equations





The Attempt at a Solution


I am not sure where to begin.
 
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Bones said:

Homework Statement



An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.6 times the mass of the other. If 25000 J is released in the explosion, how much kinetic energy does each piece acquire?

Homework Equations



The Attempt at a Solution


I am not sure where to begin.

Here is a similar problem:
https://www.physicsforums.com/showthread.php?t=267683
 
Ok so m1=1.6m2
How do I figure out v1?
 
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Would v1 be 1/1.6v2?
 
Bones said:
Would v1 be 1/1.6v2?

It depends on which piece is the heavier.

What must be true in this problem?
 
The heavier piece will have less velocity than the lighter piece.
 
25000 J = 2.6/1.6 * 1/2 * m2v22
So 25000J*.81=20250J for the lighter piece and 25000J-20250J=4750J for the heavier piece.
Is that correct??
 
Bones said:
25000 J = 2.6/1.6 * 1/2 * m2v22
So 25000J*.81=20250J for the lighter piece and 25000J-20250J=4750J for the heavier piece.
Is that correct??

Not quite.

They want the KE of the pieces. And the KE is mv2/2 not mv2

Check your math.
 
I am not sure what I am doing...that was just kinda of a guess.
 
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  • #10
Bones said:
I am not sure what I am doing...that was just kinda of a guess.

25000 J = 2.6/1.6 * 1/2 * m2v22

So what does mv2/2 equal in your equation?

Isn't that the KE of m2?

Isn't that 1 part of what they asked?
 
  • #11
So 25000 J=2.6/1.6*1/2mv2v2^2 which is the same thing as 25000 J=2.6/1.6*mv2v2^2/2

25000J=0.8125m2v2

Am I on the right track?
 
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  • #12
Bones said:
So 25000 J=2.6/1.6*1/2mv2v2^2 which is the same thing as 25000 J=2.6/1.6*mv2v2^2/2

Yes but 25000 J = 2.6/1.6 * 1/2*m*v2 = 2.6/1.6 * KE2

Isn't the question "Find KE1 and KE2" ?
 
  • #13
Yes.
So 1.625*KE2=25000
KE2=15385J the lighter piece
KE1=9615J the heavier piece
?
 
  • #14
Bones said:
Yes.
So 1.625*KE2=25000
KE2=15385J the lighter piece
KE1=9615J the heavier piece
?

That's what it looks like.
 
  • #15
Great! Thanks ;)
 
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