How to calculate leverage with complex shaped levers

  • Thread starter Thread starter Pinon1977
  • Start date Start date
  • Tags Tags
    Complex
AI Thread Summary
The discussion centers on the impact of the shape of a moment arm on torque at the axle or fulcrum point. It concludes that the shape does not affect the torque, confirming the correctness of the provided diagram. A question arises regarding the effect of gravity on the downward rotational movement of the moment arm and its influence on torque. Participants seek clarification on how the lever's outer part can remain horizontal while the inner part rotates. The conversation emphasizes understanding the mechanics of levers and torque calculations in complex scenarios.
Pinon1977
Messages
126
Reaction score
4
1. The problem statement, all variables and given/known

Does the shape or profile of a moment arm impact the torque created at the axel or fulcrum point

Homework Equations



T=fd[/B]

The Attempt at a Solution



Please see sketch is the torque created at position 1 in position to correct?
 

Attachments

  • 20180228_203429_Burst01.jpg
    20180228_203429_Burst01.jpg
    42.6 KB · Views: 481
Physics news on Phys.org
Pinon1977 said:
1. The problem statement, all variables and given/known

Does the shape or profile of a moment arm impact the torque created at the axel or fulcrum point

Homework Equations



T=fd[/B]

The Attempt at a Solution



Please see sketch is the torque created at position 1 in position to correct?
The shape does not matter. Your diagram is correct.
 
Thanks. So what if the moment arm is attached to an axel (depicted in the drawing as a dot) while at the same time being pulled downward by gravity. How does that downward, rotational movement affect the torque at the axel. Thanks.
 
Pinon1977 said:
Thanks. So what if the moment arm is attached to an axel (depicted in the drawing as a dot) while at the same time being pulled downward by gravity. How does that downward, rotational movement affect the torque at the axel. Thanks.
I'm not seeing how that is a different scenario from that depicted in your original diagram.
Can you explain more clearly what this second scenario is?

A question: how is it arranged that the outer part of the lever remains horizontal as the inner part rotates?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top