How to Calculate Moist Air Dehumidification and Cooling Rates?

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To calculate moist air dehumidification and cooling rates, start by determining the mass flow rate of dry air, which is found to be 311.61 kg/min. Next, calculate the water removal rate, resulting in 11.40 kg/min. Finally, assess the required refrigeration capacity, which is calculated to be -181.91 tons. The process involves understanding the relationships between temperature, relative humidity, and air flow rates. A clear explanation of the underlying principles and equations is essential for solving such problems effectively.
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Homework Statement



Moist air at 40 C and 90% R.H. enters a dehumidifyer at the rate of 300 m3/min. The condensate and the saturated air exit at 10oC through separate exits. The pressure remains constant at 100 kPa. Determine (a) the mass flow rate of dry air, (b) the water removal rate, and (c) the required refrigeration capacity in tons.

Answers: (a) 311.61 kg/min, (b) 11.40 kg/min, (c) -181.91 tons

I tried everything I know in my scratch but this topic does not teach by my professor. I read some books and research. However, I still do not get the answer. Just explain to me how to solve this kind of problems
 
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please explain this to me
 
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