How to Calculate the Atomic Mass of an Unknown Element M in MCl?

AI Thread Summary
To calculate the atomic mass of the unknown element M in MCl, one must first analyze the reaction with AgNO3 that produces 2.6091 grams of AgCl. Understanding the stoichiometry of AgCl reveals the ratio of silver and chlorine atoms, which is essential for determining the mass contributions of each element. The initial mass of MCl (0.7718 grams) must be used alongside the mass of AgCl to deduce the mass of chlorine and subsequently the mass of M. Additional chemical data, such as the molar masses of Ag and Cl, is necessary to complete the calculation. Ultimately, the atomic mass of M can be derived from the relationship established through these calculations.
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unknown ellement called M reacts with Cl to make MCl
0.7718 gram of MCl reacts with AgNO_3 as a result we get
2.6091 gram of AgCl.
what is the atomic mass of M
??
 
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You are not supposed here to ask like that, but to show enough effort to show where you got stuck or made a mistake. However I will tell you you cannot solve this with only the data in the question, you were either given or expected to be able to access other general chemical information.

You might start with the 2.6091 gram of AgCl. I guess from the formula you know what is the ratio of Ag and Cl atoms in AgCl? Can you work out the ratio of grams of Ag and Cl? For that you need information that is not written above. Maybe you can think what you need and then where to find it. From that you may start thinking about the M.
 
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