How to Calculate the Minimum Number of Lines to Resolve Sodium Spectrum Lines?

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Hi, i exam is coming up in a week and i have no clue so wat ever on how to solve this question.
How do i calculate the minimum number of lines?

What i need to answer to have full marks??

Q:

The Sodium vapor spectrum contains two bright yellow lines which have almost the same
wavelength (589.0 nm and 589.6 nm). Calculate the minimum number of lines required
in a grating which can resolve these lines in the second order.
:(

if you have some spare time, please help me out.
 
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You know that the resolving power is given by R = \frac{\lambda}{\Delta\lambda}. But we also have the diffraction law which states a\sin{\theta} = m(\lambda + d\lambda) so R = m N where m is the order of the diffraction and N the total number of slits in the grating. So what you want to do is to first calculate the resolving power, and then just divide by the diffraction order to obtain N :wink:
 
Arowana, you are supposed to show your effort before asking for help !

Pietjuh, please require that students asking for help first show what they've tried.

And to both of you, please read the posting guidelines.
 
THanks Pietjuh , and sorry for getting you in trouble.
 
Arowana, try looking at your laboratory manual Experiment 44, Diffraction Grating.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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