How to calculate the weight of a submerged hollow cylinder?

AI Thread Summary
To calculate the maximum weight of a submerged hollow cylinder being lifted, the focus should be on the mass of the cylinder itself, which is 2 tons, as the water inside will flow out when the cylinder is raised. The buoyant force does not contribute to the lifting weight since the water exits the cylinder as it is pulled up. The crane's lifting capacity should primarily account for the mass of the steel pipe, as the water does not add to the load during the lift. It is essential to consider the cylinder's dimensions to determine the volume of water it can hold, but this water will not affect the crane's lifting requirements. Ultimately, the crane only needs to lift the mass of the hollow cylinder itself.
shaufie
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A hollow cylinder (2 tons) is dipped in a chemical tank using hoist crane for treatment purpose.
Can anyone please help me to show how to calculate the maximum weight of the submerged hollow cylinder when it is being pulled up because I need to choose the correct lifting capacity for the crane. Is it related to the buoyant force? I need to know the maximum weight of the water inside the hollow that the crane need to lift. Thank you.
 

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Is there a way the water can be caught in the cylinder at all ? Looks to me it can flow out easily, so all you need to worry about is the mass of the steel pipe.
Proivded it goes slow enough.
 
the hollow cylinder is totally submerged in the chemical tank in a horizontal position so the crane will pull up not only the cylinder but also the water inside the hollow and when it reach the surface the water will flow out from the cylinder which will make it lighter. Can i just calculate the mass of the water based on the hollow dimension or is there any relation with buoyant force?
 
Crane doesn't lift the water (it flows out sideways), so pipe mass is basically all it has to pull.
 

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