How to calculate work done using a graph

AI Thread Summary
To calculate work done in an engine cycle using a p-v graph, the work is represented by the area enclosed by the graph. If only a picture of the graph is available, counting the full squares within the closed area is a practical method, while half squares should also be included for a more accurate measurement. For precise calculations, tools like Photoshop or a planimeter can be used to measure the area. The units of the calculated area will correspond to pressure multiplied by volume, ultimately representing work in terms of force times length. Understanding these concepts allows for effective work calculation using graphical methods.
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Can someone please tell me how do i calculate work done in 4 process of engine cycles using a graph?

i drew the p-v graph of an gasoline engine cycle now i don't know how to calcualte work done. is it by calculating the area inside or how?

no need of formulas...just using the graph..

WORK DONE USING A GRAPH !
 
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now graphically means do i need to just count the Squares in the closed area or is there any formula to use to find it?
 
How are you given the graph? Just a picture or are you given a formula? If all you have is a picture, the "counting squares is all you can do. If you are given a formula you can integrate over the area or perhaps integrate around the boundary and use Green's Theorem.
 
Thanks hallsofIvy

Just a picture. now becaususe it's a p-v diagram. i got 31 full squares. i didnt count the half squares which are halfed because of the curve. do i need to count them all as well?

and if it's 31 then what is the unit do i have to use for the answer?
 
You should count them all. You could try scanning the image into Photoshop or similar, calibrating the scale of the squares to pixels and then measuring the area. Or you could use a planimeter - that's typically how you would measure it from an indicator diagram from an engine.

As for units, you know that you're looking for the area of a pressure-volume plot. Thus the units of your area should be the same as the units of pressure multiplied by the units of volume. In an MLT system (mass, length, time) your units should be equivalent to:

ML^{2}T^{-2}

or in other words, equivalent to a force times a length, which gives you work.
 
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