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I am using impulse-momentum theorem in problem solving. But I am quite confusing about deal with the direction of momentum so always get the wrong sign.
For example, assume a long thin bar with mass M and length L hanging from a fixed frictionless point A at the ceiling, the bar is stay at rest. Now a bullet with mass m and initial velocity v_0 moving horizontally towards the bar and hit it at point B (the distance b/w A and B is y). Finally, the bullet embed into bar and then moving together with it. The instantaneous horizontal impulse when it hit the bar is I_b, find the intial angular velocity of the bar.
Since the system's total momentum is conserved, we can write
<br /> mv_0 = (m+M)V_f<br />
and the change of the momentum of the bullet is the impulse
<br /> MV_f = -m(v_f-v_0) = -I_b<br />
then the initial angular momentum of bar can be given by
<br /> L = MV_f y = -I_b y<br />
After collision, the bar (and the bullet) move around pivot A, the moment of inertia about A is I=ML^2/3 (ignore the mass of bullet). With the help of following equation
L = I\omega
we find that
\omega = \frac{L}{I} = - \frac{3I_b y}{ML^2}
the result (the value) is correct, but it should be positive. I have no idea where is the mistake come from.
For example, assume a long thin bar with mass M and length L hanging from a fixed frictionless point A at the ceiling, the bar is stay at rest. Now a bullet with mass m and initial velocity v_0 moving horizontally towards the bar and hit it at point B (the distance b/w A and B is y). Finally, the bullet embed into bar and then moving together with it. The instantaneous horizontal impulse when it hit the bar is I_b, find the intial angular velocity of the bar.
Since the system's total momentum is conserved, we can write
<br /> mv_0 = (m+M)V_f<br />
and the change of the momentum of the bullet is the impulse
<br /> MV_f = -m(v_f-v_0) = -I_b<br />
then the initial angular momentum of bar can be given by
<br /> L = MV_f y = -I_b y<br />
After collision, the bar (and the bullet) move around pivot A, the moment of inertia about A is I=ML^2/3 (ignore the mass of bullet). With the help of following equation
L = I\omega
we find that
\omega = \frac{L}{I} = - \frac{3I_b y}{ML^2}
the result (the value) is correct, but it should be positive. I have no idea where is the mistake come from.