How to deal with non fixed springs?

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To analyze a system with non-fixed springs, one must consider the forces acting on each block and the spring's tension. When two blocks are connected by a spring and a horizontal force is applied, the tension in the spring can be calculated using the formula T = k (ΔxB - ΔxA), where k is the spring constant and Δx represents the displacements of each block. The acceleration of each block can be determined by applying Newton's second law, taking into account the net force acting on each block, which includes the tension from the spring. The system's dynamics will depend on the relationship between the applied force, the spring's tension, and the masses of the blocks. Understanding these principles allows for accurate predictions of motion in systems with non-fixed springs.
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Hello

In every physics book they explain how to compute the force that a spring exert if one of its ends is fixed to a wall (or equivalent) and the other end is compressed or stretched.

But how to deal with the problem if both ends are 'free'.

For example, suppose you have two blocks attached with a spring, and someone apply an horizontal force of, say, 50N. (Lets suppose that there is no friction with the surface, the blocks are originally at rest, the spring is originally in its relaxed state, and the spring constant is, say, 300N/m).

How you would compute the acceleration of each block?

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The tension in the spring (assumed mass-less) is equal to the spring constant times the displacement of mass B minus the displacement of mass A:

T = k (ΔxB-ΔxA)

This difference in displacements is the amount that the spring stretches.

Chet
 
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