How to Design a Solenoid for an Electric Door Lock Releaser?

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To design a solenoid for an electric door lock releaser, it must generate a magnetic field strong enough to exert at least 10 N of force from a distance of 1 cm while operating at 12V. The key parameters to determine include the number of wire turns, wire diameter, and iron core specifications. The magnetic field strength can be calculated using the formula B = μNI, where μ is the permeability of the core material, N is the number of turns, and I is the current. To calculate the force exerted on the iron at a distance, additional equations involving the magnetic field strength and the characteristics of the iron piece are needed. Understanding these calculations is crucial for effective solenoid design.
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I am trying to make a an electric door lock releaser. I am going to use a solenoid to make an electromagnet that will pull down a handle to release the lock. The electromagnet has to act from a distance of 1 cm. And it has to impart a force of at least 10 N. The problem is to design the electromagnet to operate at 12v. I mean to ask, how many turns of wire?, what diameter of wire and the iron-core?. Whats the method to find them?
 

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Put it in short my question is--
, Given a solenoid, you can find the magnetic field strength by B = uNI.
But How do I calculate how much force this field will impart in a piece of iron some distance away?
 
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