How to Determine Energy Probabilities in an Infinite Potential Well?

Firben
Messages
141
Reaction score
0

Homework Statement



The wave function for a particle in a infinitely deep potential well is at some point in time Φ(x) = Nx(a-x). In which probability gives the energy measurment a another value than E1 ,etc ground state

Homework Equations



1 = |cn|^2 = |<Φn|Ψ>|^2 (1)

The Attempt at a Solution


[/B]
If Ψn(x) = sqrt(2/a)sin(n*(pi)*x/a) be the eigenfunction and put it into (1) and integrate. Is this right method I am doing ?
 
Physics news on Phys.org
What are you asked to do in this problem? Initially I supposed you have to calculate the expansion coefficient, but equation (1) indicate that it's equal to unity (which is not correct either). Is it the N in ##\Phi(x)## that is asked? In that case simply use the requirement of normalization.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top