How to Determine the Coefficients of a Cubic Function with Given Conditions?

dontdisturbmycircles
Messages
592
Reaction score
3

Homework Statement


Find a,b,c, and d such that the cubic f(x)=ax^{3}+bx^{2}+cx+dsatisfies the indicated conditions.

Relative maximum (3,3)
Relative minimum (5,1)
Inflection point (4,2)

Homework Equations





The Attempt at a Solution




I am so lost as to how to do this :/.

Its a polynomial so f ' (x) must = 0 at x=3 and x=5 (can't not exist), and I also know that the derivative of f(x) will be a function of degree 2, which can have at most two roots. Thus the function must be of the form a(x-3)(x-5)=f ' (x), right?

I know that the second derivative is defined for all x (can't have negative exponents, they would become constants before that point). And that f '' (x)=0 at x=4...

I just can't see how to piece it all together. Can someone help me out?
 
Physics news on Phys.org
Work out the explicit form of the first and second derivatives of f. Then plug in x=3 and x=5 into the first derivative, which you said must be zero. Plug in x=4 into the second derivative, which again, you said must be zero. This will give you 3 equations in 3 unknowns, which you can solve.
 
f'(x)=3a(x-3)(x-5)\equiv 3ax^2 +2bx +c

is a place to start.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top