How to Determine the Minimum Diameter of an Alloy Cable for a Specific Load?

AI Thread Summary
To determine the minimum diameter of an alloy cable required to support a load of 15 kN with a tensile strength of 75 MPa, the relationship between tensile strength, force, and area must be understood. The tensile strength is expressed as force per unit area, calculated as 75 MPa or 75,000,000 N/m². The load of 15 kN translates to 15,000 N, which must be supported by the cable's cross-sectional area. By rearranging the formula for tensile strength (stress = force/area), the necessary area can be calculated, leading to the conclusion that a diameter of 1.6 cm is required. Understanding these calculations is crucial for ensuring the cable can safely support the specified load.
benhorris
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Having a bit of a problem with this question,

Find the minimum diameter of an alloy cable, tensile strength 75 MPa, needed to support a load of 15 kN.

I know the answer is 1.6cm but i need someone to help explain how to get it.

Ive got this far...

Tensile strength of cable = 75 MPa = 75 000 000 Newtons per square meter
= 7.5 x 10^7 m^-2
The weight material required to hold = 15kN = 15 000 N
 
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Look at the units.

Tensile Strength is a measure of stress, or force per unit area.
 

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