How to determine the volume of a region bounded by planes?

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Homework Statement


Let G be the region bounded by the planes x=0,y=0,z=0,x+y=1and z=x+y.

Homework Equations



(a) Find the volume of G by integration.
(b) If the region is a solid of uniform density, use triple integration to find its center of mass.

The Attempt at a Solution


[/B]
My understanding is that I need to setup a triple integral:

∫∫∫dxdydz

I’m just a little unsure about how to determine the terminals
 
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Did you draw a sketch?

You can always find boundaries for e.g. z as function of x,y and boundaries for y as function x, but sometimes there are easier methods.
 
Have you drawn a picture? That's the first step. Maybe this will help:
object.jpg
 

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mfb said:
Did you draw a sketch?

You can always find boundaries for e.g. z as function of x,y and boundaries for y as function x, but sometimes there are easier methods.
So would the boundaries be:

0≤z≤x+y
0≤y≤1-x
0≤x≤1
 
That will work.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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