How to differentiate y = ln( 1+x^2)^1/2

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Homework Help Overview

The problem involves differentiating the function y = ln(1+x^2)^(1/2), which is related to logarithmic differentiation and the application of the chain rule.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the power rule and chain rule in differentiation. There is a suggestion to clarify the function's form, with one participant noting a potential misunderstanding regarding the expression of the logarithm. Questions arise about the treatment of constants in differentiation.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the function and clarifying rules of differentiation. Some guidance has been offered regarding the simplification of the logarithmic expression, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants are addressing potential confusion around the differentiation rules and the correct interpretation of the logarithmic function. There is an indication of differing understandings of how constants behave during differentiation.

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Homework Statement



hey guys, got a question. how do you differentiate y=ln(1+x^2)^1/2. any help would be appreciated, thanks

Homework Equations



answer is x/(1+x^2)

The Attempt at a Solution

 
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Power rule and chain rule.
 


To get the answer you have listed your function must be [itex]\ln \sqrt{1+x^2}[/itex] and not [itex]\sqrt{\ln(1+x^2)}[/itex]. You can write [itex]\ln \sqrt{1+x^2}=\frac{1}{2}\ln (1+x^2)[/itex], perhaps this form is less intimidating?
 


so the 1/2 just stays out the front without it being differentiate, i thought it dissapeared? thanks for the replys
 


geffman1 said:
so the 1/2 just stays out the front without it being differentiate, i thought it dissapeared? thanks for the replys
Go check your rules of differentiation again...
 

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