How To Evaluate Complex Numbers

urduworld
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Hi PFs



i want to know how to evaluate the complex number, and what are the meaning of the evaluating a complex number



Let Z be the complex number, Z = (3-4i)^5 what i have to do, just give me hint
 
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urduworld said:
Hi PFs



i want to know how to evaluate the complex number, and what are the meaning of the evaluating a complex number



Let Z be the complex number, Z = (3-4i)^5 what i have to do, just give me hint

Put the complex number into its polar representation: r.e.
 
its polar representation is Z = r[Cos(thita) + iSin(thita)]
is it is Evaluation
i want to know what actually i have to do in evaluation
Thanks for your help :)
 
urduworld said:
its polar representation is Z = r[Cos(thita) + iSin(thita)]
is it is Evaluation
i want to know what actually i have to do in evaluation
Thanks for your help :)

You need to go in the reverse direction, using x and y as your variables, not r and θ. Can you complete the following with substitutions for r and θ in terms of x and y?

r^{i\theta} = x + iy​

Alternatively, can you rewrite 3-4i into polar form, to, say, four decimal places?

Cheers -- sylas
 
i was thinking that evaluation is like polar form i don't know how to resolve this, i know nothing about
r^{i\theta} = x + iy
please tell me what i have to do,
 
To find powers you need "DeMoivre's formula":
(r[cos(\theta)+ i sin(\theta)])^n= r^n (cos(n\theta)+ i sin(n\theta)).

If DeMoivre's formula is not in your text, did you consider just sitting down and multiplying 3- 4i by itself 5 times? That would probably have been faster.
 
oOps this is like that yes Demorvies theorem is in mine book, i have to apply this, and is n will the power like 0,1,2...n
 
urduworld said:
i was thinking that evaluation is like polar form i don't know how to resolve this, i know nothing about
r^{i\theta} = x + iy
please tell me what i have to do,

I fool so feelish...

HallsofIvy is quite right; simply multiplying it is probably the easiest thing to do when you have an integer exponent.

For example:
(3-4i)(3-4i) = 9 - 24i + 16i^2 = 9 - 16 - 24i = -7 -24i​
Keep going from there. Multiply by (3-4i), and again, and once more. You don't need the polar form.

However, since I mentioned it, I'd better go ahead with the answer:
\sqrt{x^2+y^2} \times e^{\text{atan2}(y, x) i} = x + iy​
You don't need to worry about this if you take HallsofIvy's hint about repeated multiplications.

Cheers -- sylas
 
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